Solution:
Total no of bases= 160×2= 320
According to Chargaff's rule A=T and G=C
So A=20% then T= 20%
Therefore G= 30% C=30%
Cytosine bases= 320×30/100= 96
A DNA molecule is 160 base pairs long. If it has 20% adenone, how many cytosine bases are present in this DNA molecule?
Total no of bases= 160×2= 320
According to Chargaff's rule A=T and G=C
So A=20% then T= 20%
Therefore G= 30% C=30%
Cytosine bases= 320×30/100= 96