In the change of ${NO}^{+}$ to $NO$ , the electron is added to

A
$σ$ orbital
B
$π$ - orbital
C
$σ^{*}$ orbital
D
$π^{*}$ orbital

Solution:

M.O. configuration of ${NO}^{+}$ is : $(σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{z})}^{2} {(π 2 p_{x})}^{2} {(π 2 p_{y})}^{2}$
M.O. configuration of NO is :
$\begin{array}{r} (σ 1 s)^{2} {(σ^{*} 1 s)}^{2} (σ 2 s)^{2} {(σ^{*} 2 s)}^{2} {(σ 2 p_{x})}^{2} {(π 2 p_{x})}^{2} \\ {(π 2 p_{y})}^{2} {(π^{*} 2 p_{y})}^{1} \end{array}$
So, an electron is added to $π^{*}$ orbital.

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