The density of 2 M aqueous solution of NaOH is 1.28 g/cm3. The molality of the solution is [Given that molecular mass of NaOH = 40 g mol-1]

Let, volume of solution = 1 litre
Mole of NaOH = 2
Mass of NaOH solution = 1000 × 1.28 = 1280 g
Mass of $H_{2}$ O = (1280 – 2 × 40) = 1200 g = 1.2 kg

$Molality (m) = \frac{Mole of NaOH}{Mass of solvent (kg)}$

$\begin{array}{l} = \frac{2}{1.2} \\ = 1.67 m \end{array}$

Onam Program Names

Zoom Earth Live

The density of 2 M aqueous solution of NaOH is 1.28 g/ ${cm}^{3}$ . The molality of the solution is [Given that molecular mass of NaOH = 40 g ${mol}^{- 1}$ ]