The weight of a molecule of the compound C60H122 is

The weight of a molecule of the compound $C_{60} H_{122}$ is

A
$1 .4 \times 10^{- 21} g$
B
$1 .09 \times 10^{- 21} g$
C
$5 .025 \times 10^{23} g$
D
$16 .023 \times 10^{23} g$

Solution:

$\begin{array}{l} Molecular weight of C_{60} H_{122} = 12 \times 60 + 122 \times 1 \\ = 720 + 122 = 842 \\ ∵ 6 \times 10^{23} molecules of C_{60} H_{122} has mass = 842 g \\ ∴ 1 molecule of C_{60} H_{122} has mass \frac{842}{6 \times 10^{23}} \\ = 140 .333 \times 10^{- 23} g \\ = 1 .4 \times 10^{- 21} g . \end{array}$

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