MathematicsA chord AB of a circle, of radius 14 cm  makes an angle of 60° at the center of the circle. Find the area of the minor segment of the circle. (Use π=227 ).

A chord AB of a circle, of radius 14 cm  makes an angle of 60° at the center of the circle. Find the area of the minor segment of the circle. (Use π=227 ).


  1. A
    17.8 cm2
  2. B
    17.6 cm2
  3. C
    15.8 cm2
  4. D
    17.5 cm2 

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    Solution:

    Given that,
    Radius=14 cm , θ=60.
     Area of sector OACB=θ360×πr2
    60360×π(14)2 102.67 cm2 Area of equilateral triangle =34×side2 ΔAOB=34×142  84.87 cm2  Area of minor segment = Area of sector - Area of triangle
    102.67-84.87 17.8 cm2 Thus, the area of the minor segment of the circle is 17.8 cm2 .
    Hence, option 1 is correct.
     
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