A die is thrown. Find the probability of getting a multiple of 2 or 3.

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A
$\frac{2}{3}$
B
$1$
C
$0$
D
$2$

Solution:

Given that a die is thrown.
A die consists of six sides and it has

1, 2, 3, 4, 5

and

6

dots.
The multiples of

2

are

4, 6

and multiples of

3

6

only.
Let us assume that the probability of getting a multiple of

2 or 3

= P (A)

.
As we know that probability can be find with the formula is,

Probability = \frac{Number of favorable outcomes}{total number of outcomes}

Multiples of both

2

3

are

2, 3, 4

and

6 .

It means there are

4

favorable outcomes out of total

6

.
So using the formula,

\Rightarrow P (A) = \frac{4}{6}

\Rightarrow P (A) = \frac{2}{3}

So,The probability of getting multiples of

2 or 3

\frac{2}{3}

.
Hence, the option

1

is correct.

A die is thrown. Find the probability of getting a multiple of $2 or 3$ .

Solution:

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