MathematicsA man buys 9 oranges for Rs. 16 and sells 11 for Rs. 20. What is his gain or lose percent?

A man buys 9 oranges for Rs. 16 and sells 11 for Rs. 20. What is his gain or lose percent?

Given, a man buys 9 oranges for Rs. 16 and sells 11 for Rs. 20.
Allow 99 oranges to be purchased.
(L.C.M. of 9 and 11)
The cost of 99 oranges = (11

\times 16

)
= Rs. 176.
The selling price is = (9

\times 20

)
= Rs. 180.
Since, selling price is greater than the cost price, there is gain.
Gain

= Selling price - Cost price

= Rs. (180-176)
= Rs. 4 We know that,
Gain% =

\frac{Gain}{Cost Price}

×100
∴ Gain% =

\frac{4}{176}

×100
= 2

\frac{3}{11}

% .
Therefore, the gain percent earned by the man is 2

\frac{3}{11}

%.
Hence, option 3 is correct.

JEE