A(adj A) is equal to

$A (a d j A)$ is equal to

A
$I$
B
$| A | I$
C
$O$
D
$| A |^{n} I$

Solution:

$A (a d j A) = | A | I_{n} = (a d j A) A$ , where $A$ is any square matrix of order $n$ .

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