If  M is the mid – point of the hypotenuse AC of right ΔABC then BM=

If  M is the mid - point of the hypotenuse AC of right ΔABC then BM=

  1. A
    AC
  2. B
    2AC
  3. C
    12 AC
  4. D
    13 AC

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    Solution:

     

     

     

     

     

    Given in ΔABC,B=90° and AM=MC Produce BM to D such that BM=MD

    ΔABMΔDCM

    AM=MC

    AMB=CMD(V.O.A.E)

    BM=MD

      By S.A.S congruence ΔABMΔCDM

    AB=CD

    BAM=MCD

    AB||DC

    DCB=90°

    ΔABCΔDCB

    AC=BD

    AC=2BM

    BM=12AC

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