Search for: MathematicsIf sin 3A=cos (a-26∘), where 3A is an acute angle. find the value of A. If sin 3A=cos (a-26∘), where 3A is an acute angle. find the value of A. A32∘B30∘C29∘D24∘ Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:Given, sin 3A=cos (A-26∘), where 3A is an acute angle.Use the identity,cos 90∘-θ=sin ASimplify the given expression. sin 3A=cos (A-26∘)⇒cos 90∘-3A=cos (A-26∘)⇒90∘-3A=A-26∘⇒4A=116∘⇒A=29∘Therefore, the value of A is 29∘.Hence, option 3 is correct.