MathematicsIf sin 3A=cos (a-26∘), where 3A is an acute angle. find the value of A.

If sin 3A=cos (a-26∘), where 3A is an acute angle. find the value of A.


  1. A
    32∘
  2. B
    30∘
  3. C
    29∘
  4. D
    24∘ 

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    Solution:

    Given, sin 3A=cos (A-26∘), where 3A is an acute angle.
    Use the identity,
    cos 90∘-θ=sin A
    Simplify the given expression.
    sin 3A=cos (A-26∘)
    ⇒cos 90∘-3A=cos (A-26∘)
    ⇒90∘-3A=A-26∘
    ⇒4A=116∘
    ⇒A=29∘
    Therefore, the value of A is 29∘.
    Hence, option 3 is correct.
     
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