Solution:
In a triangle, P, Q and R are the mid-points of sides BC, CA and AB respectively. If AC = 21 cm, BC = 29 cm and AB= 30 cm, the perimeter of the quadrilateral ARPQ is 51 cm.Given a triangle in which P, Q and R are the mid-points of sides BC, CA and AB respectively and AC = 21 cm, BC = 29 cm, AB= 30 cm.
Hence, ARPQ is a parallelogram.
The measure of side is,
Opposite sides are equal,
AR = QP
⇒ QP = 15 cm
Also,
Also, opposite sides are equal
RP = AQ
⇒ AQ = 10.5 cm
The perimeter is,
P = sum of all sides
Hence, the perimeter is 51 cm.