Solution:
It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992.Let the event where in 2 students have the same birthday E.
Given, P(E) = 0.992
We know that,
P(E) + P(not E) = 1
P(not E) = 1 – 0.992
P(not E) = 0.008
Hence, the probability that the students have the same birthday is 0.008.
Therefore, option 1 is correct.
