MathematicsSolve the following equations by substitution method.3a-2b=-10, 2a+3b=2.

Solve the following equations by substitution method. $3 a - 2 b = - 10, 2 a + 3 b = 2$ .

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A
$a = - 2, b = 2$
B
$a = - 1, b = 2$
C
$a = - 4, b = 2$
D
$a = - 7, b = 2$

Solution:

The given equations are,

3 a - 2 b = - 10,

2 a + 3 b = 2

From first equation we have,
⇒

a = \frac{2 b - 10}{3}

Put the value of a in the second equation.
⇒

2 \times \frac{2 b - 10}{3} + 3 b = 2

⇒

4 b - 20 + 9 b = 6

⇒

13 b = 26

∴ b = 2

Putting the value of b in the first equation.
⇒

a = \frac{2 b - 10}{3}

⇒

a = \frac{2 (2) - 10}{3}

⇒

a = - 2

Therefore,

a = - 2

and

b = 2

.
Hence, the correct option is 1.

Solve the following equations by substitution method. $3 a - 2 b = - 10, 2 a + 3 b = 2$ .

Solution:

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