MathematicsSolve the following equations by substitution method.3y-2x=9, 2x+5y=15.

Solve the following equations by substitution method. $3 y - 2 x = 9, 2 x + 5 y = 15$ .

The given solutions are,

3 y - 2 x = 9

… (1)

2 x + 5 y = 15

… (2)
From (1),
⇒

y = \frac{9 + 2 x}{3}

Putting the value of y in (2),
⇒

2 x + 5 \times \frac{9 + 2 x}{3} = 15

⇒

6 x + 45 + 10 x = 45

⇒

16 x = 0

⇒

y = \frac{9 + 2 x}{3}

⇒

y = \frac{9 + 2 (0)}{3}

⇒

y = 3

Therefore, x = 0, y = 3.
Hence, the correct option is 4.

JEE