Solve the following pairs of equations, graphically.4x+3y=1 and 2x-y=3.

Given,

4 x + 3 y = 1,

\Rightarrow y = \frac{1 - 4 x}{3}

.
Substituting different values of

x

to get corresponding values of

y

, we get

(0, \frac{1}{3}), (1, - 1), (- 1, \frac{5}{3}), (2, - \frac{7}{3}), (- 2, 3)

.
Plotting these points on the graph, we get the graph of the equation,

4 x + 3 y = 1

.
Similarly,
Given second equation,

2 x - y = 3

\Rightarrow y = 2 x - 3

Substituting different values of

x

to get corresponding values of

y

, we get

(1, - 1), (0, - 3), (2, 1), (- 1, - 5), (3, 3)

Plotting these points on the graph, we get the graph of the equation,

2 x - y = 3

.
The point of intersection of the graphs of the lines is the solution of the equations which is

(1, - 1)

Hence, the correct option is 2.

Solve the following pairs of equations, graphically. $4 x + 3 y = 1$ and $2 x - y = 3$ .