MathematicsSolve the following simultaneous equations by the method of equating coefficients. 3x-4y=7, 5x+2y=3.

Solve the following simultaneous equations by the method of equating coefficients. $3 x - 4 y = 7, 5 x + 2 y = 3$ .

Given equations are,

3 x - 4 y = 7

...(1)

5 x + 2 y = 3

...(2)
On multiplying (1) by 5 and (2) by 3 and subtracting, we get,
⇒

15 x - 15 x - 20 y - 6 y = 35 - 9

⇒

- 26 y = 26

⇒

y = - 1

On putting

y = - 1

in (1), we get,
⇒

3 x - 4 (- 1) = 7

⇒

x = 1

∴ x = 1, y = - 1

.
Hence, the correct option is 1.

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