Solution:
Given point is P (−3, −4).We know that if both coordinates are negative then point Lies in the III quadrants.
As we can observe, in given point P (−3, −4) both coordinates are negative.
Let us plot the point P (−3, −4) on the graph paper.
We know, the distance of a point P(x, y) from the x-axis is |y| units.In the above figure, we observe that the distance of point P(- 3, - 4) from the X-axis is 4 (distance is always positive).
Hence, the distance of the point P (−3, −4) from the x-axis (in units) is 4.
The correct option is (3).
