The probability of getting at least one head if three unbiased coins are tossed is

A
$\frac{1}{2}$
B
$\frac{7}{8}$
C
$\frac{5}{8}$
D
$\frac{1}{8}$

Solution:

Concept: Probability of getting probability of the occurrence of an event is $P (E) = \frac{Total number of favorable outcomes}{Total number of outcomes}$ .

Here, the sample space $= {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}$

That is, $n (S) = 8$

Let $E$ is the event of getting at least one head.

Then, $E = {TTH, THT, HTT, THH, HTH, HHT, HHH}$

Now, $n (E) = 7$

Thus, $P (E) = \frac{n (E)}{n (S)} = \frac{7}{8}$ .

Hence, the probability of getting at least one head if three unbiased coins are tossed is $\frac{7}{8}$ .

The probability of getting at least one head if three unbiased coins are tossed is

Solution:

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