Solution:
Three tankers contain 403 liters, 434 liters and 465 liters of diesel respectively and the maximum capacity of a container that can measure the diesel of the three containers exact number of times is 31 liters.
It is given that three tankers contain 403 liters, 434 liters and 465 liters of diesel respectively.
Prime factorization of 403, 434 and 465 is given by,
The factors of numbers are,
403 = 13 × 31
434 = 2 × 7 × 31
465 = 3 × 5 × 31
Therefore,
HCF of 403, 434 and 465 is 31.
Hence, the maximum capacity of a container that can measure the diesel of the three containers the exact number of times is 31 liters.
