A ball weighing 4 kg of density 4000 kg/m3 is completely immersed in water of density1000 kg/m3. The value of buoyant force acting on the ball is [[1]] N.(Take g = 10 m/s2)

The value of buoyant force acting on the ball is

10 N

.
The value of the buoyant force is equal to the weight of the water displaced by the ball.
Given,
Mass of ball

= 4 kg

Density of ball

= 4000 kg / m^{3}

As we know,

Density = \frac{Mass}{volume}

\Rightarrow

4000 = \frac{4}{volume of ball}

\Rightarrow

Volume of ball

= \frac{1}{1000} m^{3}

Volume of water displaced

=

Volume of ball

\Rightarrow

Volume of water displaced

= \frac{1}{1000} m^{3}

Mass of water displaced

=

Density of water

\times

Volume of water displaced

\Rightarrow

Mass of water displaced

= 1000 \times \frac{1}{1000}

= 1 kg

Weight of water displace

= mg

= 1 \times 10

= 10 N

Hence, the value of buoyant force acting on the ball is

10 N

A ball weighing $4 kg$ of density $4000 kg / m^{3}$ is completely immersed in water of density $1000 kg / m^{3}$ . The value of buoyant force acting on the ball is [[1]] $N$ .

(Take $g = 10 m / s^{2}$ )