A battery of 10 V carries 20000 C of charge through a resistance of 20 Ω. The work done in 10 s is

A battery of

10 V

carries

20000 C

of charge through a resistance of

20 Ω

. The work done in

10 s

2 \times 10^{5} J

.
It is known that “the work done is given by the product of the charge

(q)

and the voltage

(V)

of the body.” Mathematically,

W = qV

Therefore, the work done in the given case is

W = 20000 \times 10

\Rightarrow W = 200000

\Rightarrow W = 2 \times 10^{5} J

Hence, the work done is

2 \times 10^{5}

J.
Also Check:

A battery of $10 V$ carries $20000 C$ of charge through a resistance of $20 Ω$ . The work done in $10 s$ is