A body of mass 0.01 kg executes simple harmonic motion (S.H.M.) about x=0 under the influence of a force shown below : The period of the S.H.M. is

A body of mass 0.01 kg executes simple harmonic motion (S.H.M.) about $x = 0$ under the influence of a force shown below : The period of the S.H.M. is

A
1.05 s
B
0.52 s
C
0.25 s
D
0.30 s

Solution:

From graph, slope $K = \frac{F}{x} = \frac{8}{2} = 4$
$T = 2 π \sqrt{\frac{m}{K}} \Rightarrow T = 2 π \sqrt{\frac{0 .01}{4}} = 0 .3 \sec$

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