A conducting sphere of radius R is charged to a potential of v volts. Then the electric field at a distance r(> R) from the centre of the sphere would be

A conducting sphere of radius R is charged to a potential of v volts. Then the electric field at a distance r(> R) from the centre of the sphere would be

A
v/r
B
$frac{{{R^2}v}}{{{r^3}}}$
C
$frac{{Rv}}{{{r^2}}}$
D
$frac{{rv}}{{{R^2}}}$

Solution:

$V = frac{1}{{4pi {varepsilon _0}}}frac{q}{R}$
then $frac{q}{{4pi {varepsilon _0}}} = RV$

Now, $E = frac{1}{{4pi {varepsilon _0}}}frac{q}{{{r^2}}} = frac{{RV}}{{{r^2}}}$

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