A convex lens of a focal length of 10 cm is placed at a distance of 12 cm from a wall. What is the distance from the lens where an object should be placed to form its distinct real image on the wall?

A Convex lens of a focal length of

10 cm

is placed at a distance of

12 cm

from a wall. Distance from the lens

u = 60 cm

opposite side to the wall.
Given,
The Focal length of the convex lens,

f = + 10 cm

Distance of the real image from the lens,

v =

Distance of the wall from the

= + 12 cm

According to the formula,
⇒

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

So we have,
⇒

\frac{1}{u} = \frac{1}{v} - \frac{1}{f}

= \frac{1}{+ 12} - \frac{1}{+ 10}

= \frac{5 - 6}{60}

= - \frac{1}{60}

\Rightarrow u = - 60 cm

As a result, the object should be positioned

60 cm

from the lens on the side facing the wall.

A convex lens of a focal length of $10 cm$ is placed at a distance of $12 cm$ from a wall. What is the distance from the lens where an object should be placed to form its distinct real image on the wall?