A force of 10 N acts on a body of 2 kg at rest for 3 seconds. Find the kinetic energy acquired by the body in 3 seconds.

A force of

10 N

acts on a body of

2 kg

at rest for

3

seconds. The kinetic energy acquired by the body in

3

seconds will be

225 J .

Calculating the final speed of the body using the first equation of uniformly accelerated motion.
Initial speed,

u = 0 m / s

Final speed,

v = ?

Acceleration,

a = \frac{F}{m}

\Rightarrow = \frac{10 N}{2 Kg}

\Rightarrow = 5 m / s^{2}

Time,

t = 3 s

Using equation of motion;

v = u + at

\Rightarrow v = 0 + 5 \times 3 m / s

\Rightarrow v = 15 m / s

Calculating the kinetic energy using

K . E = \frac{1}{2} m v^{2}

\Rightarrow

= \frac{1}{2} \times 2 \times 15 \times 15

K . E = 225 J

A force of $10 N$ acts on a body of $2 kg$ at rest for $3$ seconds. Find the kinetic energy acquired by the body in $3$ seconds.