A particle of mass 2kg is initially at rest. A force acts on it whose magnitude changes with time. The force-time graph is shown below. The velocity of the particle at t=10 sec is

A
$75 m s^{- 1}$
B
$10 m s^{- 1}$
C
$50 m s^{- 1}$
D
$26 m s^{- 1}$

Solution:

Area under the force-time graph is impulse i.e., change in momentum.
$\Rightarrow ∆ p = \frac{1}{2} 2 \times 10 + 2 \times 10 + \frac{1}{2} \times 2 \times (10 + 20) + \frac{1}{2} \times 4 \times 20$
$\Rightarrow m (v - u) = 10 + 20 + 30 + 40$
$\Rightarrow 2 \times v = 100$
$\Rightarrow v = 50 m / s$

A particle of mass 2kg is initially at rest. A force acts on it whose magnitude changes with time. The force-time graph is shown below. The velocity of the particle at t=10 sec is

Solution:

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