A ray travelling from the air enters a liquid at an angle of 45 degrees from the normal. If the corresponding angle of refraction is 30 degrees, then the refractive index of the liquid with respect to air is [[1]].

A ray travelling from the air enters a liquid at an angle of

45 degrees

from the normal. If the corresponding angle of refraction is

30 degrees

, then the refractive index of the liquid with respect to air is

1.41

.
Given,
Incident angle

i = 45^{\circ}

And, angle of refraction

r = 30^{\circ}

Therefore, according to snells law.
The refractive index of the liquid with respect to air =

\frac{sin i}{sin r}

= \frac{\sin 45^{\circ}}{\sin 30^{\circ}}

= 1.41 .

A ray travelling from the air enters a liquid at an angle of $45 degrees$ from the normal. If the corresponding angle of refraction is $30 degrees$ , then the refractive index of the liquid with respect to air is [[1]].