An aluminium wire is stretched to make its length, 0.4 % larger. Then percentage change in resistance is:

An aluminium wire is stretched to make its length, 0.4 % larger. Then percentage change in resistance is:

A
0.4%
B
0.2%
C
0.8%
D
0.6%

Solution:

$R = \frac{ρ ℓ}{A} = \frac{ρ ℓ^{2}}{V} \Rightarrow \frac{Δ R}{R} = \frac{2 Δ ℓ}{ℓ} \Rightarrow % \frac{Δ R}{R} = 2 \times 0.4 = 0.8 %$

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