PhysicsAn electric heater of 1000 W is working daily for 5 hrs in the month of September and the rate of 1 unit of electricity is ₹ 6.00, then the total cost and end of the month is ₹[[1]].

An electric heater of 1000 W is working daily for 5 hrs in the month of September and the rate of 1 unit of electricity is ₹ 6.00, then the total cost and end of the month is ₹[[1]].


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    Solution:

    If an electric heater is rated 1000 W is operated for 5 hours and cost of 1 unit is  6, then the cost of energy is ₹ 900.
    It is given that the rating of the heater is 1000 W and is operated for the time,
           t=5 hr
    It is known that the energy consumption (E) is equal to
         E=P×t
    Where P, t is the power and the time respectively.
    On substituting the given values, we get
        E=1000×5×30
    E=150000 Wh
    E=150 kWh
    Since, 1 unit is 1 kWh and therefore energy consumed is equal to
        E=150 units
    Hence, the energy consumed by heater is 150 units.
    The energy consumed by heater is 150 unit and hence the cost of energy (C) is equal to
       C=150×6=₹ 900
    Therefore, the cost of energy is  900.
     
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