An object 2 cm high is placed at a distance of 16 cm from a concave mirror which produces a real image 3 cm high. Position of the image is -[[1]] cm.

An object

2 cm

high is placed at a distance of

16 cm

from a concave mirror which produces a real image

3 cm

high. Position of the image

- 24 cm

.
It has been given that,
Object height,

h = 2 cm

Image height,

h' = - 3 cm

(since the real image is inverted).
Object distance,

u = - 16 cm

m = \frac{h'}{h}

= \frac{- v}{u}

v = - u \frac{h'}{h}

v = - 24 cm

The image is formed at distance of

24 cm

in front of the mirror. (negative sign implies that the object and image are on the same side).

An object $2 cm$ high is placed at a distance of $16 cm$ from a concave mirror which produces a real image $3 cm$ high. Position of the image is $-$ [[1]] $cm$ .