An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. The image will be formed at a distance of [[1]] cm.

An object is placed at a distance of

10 cm

from a convex mirror of focal length

15 cm

.The image will be formed at a distance of

6 cm

.
Given that,

u = - 10 cm      f = + 15 cm    v = ?

According to the mirror formula,

\frac{1}{f} = \frac{1}{v} + \frac{1}{u}

where,

u =

the distance between the object and the pole of the mirror,

v =

the distance between the image and the pole of the mirror,

f =

focal length

\Rightarrow \frac{1}{v} = \frac{1}{f} - \frac{1}{u}

\Rightarrow \frac{1}{v}

\frac{1}{15}

- \frac{1}{- 10}

\Rightarrow \frac{1}{v}

\frac{1}{15}

+ \frac{1}{10}

\Rightarrow \frac{1}{v}

\frac{2 + 3}{30}

\frac{5}{30}

\Rightarrow v = \frac{30}{5}

\Rightarrow v = 6 cm

The image will be formed at a distance of

6 cm

from the mirror behind it. The image will be formed erect and virtual.

An object is placed at a distance of $10 cm$ from a convex mirror of focal length $15 cm$ . The image will be formed at a distance of [[1]] $cm$ .