How many 176 Ω resistors in parallel are required to carry 5 A on a 220 V line?

We know that , potential difference ,

V = 220 V

and Current

I = 5 A

By ohm’s Law,

V = I \times R

220 = 5 \times R

R = \frac{220}{5} = 44 Ω

Hence, total resistance of the circuit is

44 ohms

. Let's find how many

176 ohm

resistors should be connected in parallel. Let

x

be the required number of resistors.

\frac{1}{44} = \frac{1}{176} x

44 x = 176

Hence

x = \frac{176}{44} = 4

Therefore, 4 resistors of

176 ohm

each should be connected in parallel.

How many $176 Ω$ resistors in parallel are required to carry $5 A$ on a $220 V$ line?