If a car covers 2/5th of the total distance with  v1 speed and 3/5th of the total distance with v2 then average speed is

If a car covers 2/5th of the total distance with  v1 speed and 3/5th of the total distance with v2 then average speed is

  1. A

    12v1v2

  2. B

    v1+v22

  3. C

    2v1v2v1+v2

  4. D

    5v1v23v1+2v2

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    Solution:

    vavg=s1+s2t1+t2

    vavg=s1+s2s1v1+s2v2

     vavg =2s5+3s52s5v1+3s5v2=5v1v22v2+3v1

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