If M is the mass of earth and R is the radius of the earth, the ratio of acceleration due to gravity and gravitational constant will be

The ratio of acceleration due to gravity and gravitational constant for Earth is

M / R^{2}

.
The acceleration due to gravity,

g

on the surface of earth is calculated as,

g = \frac{GM}{R^{2}} . . . . . . . . . . . . . . . . . . . . . . . . \dots (1)

Where

G = 6.67 \times 10 - 11 N m^{2} {kg}^{- 2}

is the gravitational constant,

M

is the mass of the earth and

R

is the radius of the earth.
Rearranging the above equation (1), we get

\frac{g}{G} = \frac{M}{R^{2}}

If $M$ is the mass of earth and $R$ is the radius of the earth, the ratio of acceleration due to gravity and gravitational constant will be