If the magnification of a body of size 1 m is +2, then the size of the image is [[1]] m.

If the magnification of a body of size

1 m

+ 2

, then the size of the image is

2 m .

Given,
Size of body,

h_{1} = 1 m

Magnification,

m = 2

The magnification produced by the mirror is defined as the ratio of the height of the image to the height of the object.
We know that,

m = \frac{h_{2}}{h_{1}}

….(1)
Where

h_{2}

is the size of the image and

h_{1}

is the size of the object.
Substituting the given value in equation (1) we get

2 = \frac{h_{2}}{1}

h_{2} = 2 \times 1

h_{2} = 2 m

If the magnification of a body of size $1 m$ is $+ 2$ , then the size of the image is [[1]] $m$ .