Rajeev went from Delhi to Chandigarh and returned to Delhi on his motorbike. The odometer read 4200 km at the start of the trip and 4460 km at the end of his trip. If Rajeev took 4 h 20 min to complete his trip, then find the average velocity?

Rajeev went from Delhi to Chandigarh and returned to Delhi on his motorbike. The odometer read

4200 km

at the start of the trip and

4460 km

at the end of his trip. If Rajeev took

4 h 20 \min

to complete his trip, then the average velocity is

60 km / h

.
Given:
Here, the total distance travelled by Rajeev is

D = 4460 - 4200

= > D = 260 km

Total time,

t = 4 h 20 \min

= > t = (4 + \frac{1}{3}) h

= > t = \frac{13}{3} h

We know that

average velocity = \frac{Total distance}{Total time}

= > v = \frac{260}{\frac{13}{3}}

= > v = 60 km / h

Rajeev went from Delhi to Chandigarh and returned to Delhi on his motorbike. The odometer read $4200 km$ at the start of the trip and $4460 km$ at the end of his trip. If Rajeev took $4 h 20 \min$ to complete his trip, then find the average velocity?