Rajeev went from Delhi to Chandigarh on his motorbike. The odometer of the bike read 4200 km at the start of trip and 4460 km at the end of his trip. If Rajeev took 4 h 20 mins to complete his trip, find the average speed in m/s?

Rajeev went from Delhi to Chandigarh on his motorbike. The odometer of the bike read

4200 km

at the start of trip and

4460 km

at the end of his trip. If Rajeev took

4 h 20 mins

to complete his trip, the average speed is

16.67 m / s

.
Given,
Initial distance

= 4200 km

final distance

= 4460 km

Time,

t = 4 h 20 mins

= \frac{13}{3} hr

Therefore,
Average speed

= \frac{4460 - 4200}{\frac{13}{3}}

= 60 km / hr

= 60 \times \frac{5}{18} m / s

= 16.67 m / s

Rajeev went from Delhi to Chandigarh on his motorbike. The odometer of the bike read $4200 km$ at the start of trip and $4460 km$ at the end of his trip. If Rajeev took $4 h 20 mins$ to complete his trip, find the average speed in $m / s$ ?