Several electric bulbs designed to be used on a 220 V electric supply line are rated 10 Weach .How many bulbs can be connected in parallel with each other across the two wires of 220 V line if the maximum allowable current is 5 A?

110 bulbs can be connected in parallel with each other across the two wires of

220 V

line .
First let's calculate the resistance since voltage and Power is given in the question,

V = 220

and P = 10W
Power ,

P = \frac{V^{2}}{R}

= \frac{220^{2}}{R}

Resistance of 1 bulb,

R ` = 4840 Ω

Total resistance ,

R = \frac{V}{I}

( by ohm’s Law)

R = \frac{220}{5} = 44 Ω

Now, we know the total resistance of the circuit

= 44 Ω

. We have to find how many bulbs should be connected in parallel.
Let no. of bulbs be x .

\frac{1}{44} = \frac{1}{4840} \times x

\Rightarrow

x = \frac{4840}{44}

x = 110

Thus, 110 bulbs can be connected in parallel in this circuit.

Several electric bulbs designed to be used on a $220 V$ electric supply line are rated $10 W$ each .How many bulbs can be connected in parallel with each other across the two wires of $220 V$ line if the maximum allowable current is $5 A$ ?