The angle between two vectors given by 6i¯+6j¯−3k¯ and 7i¯+4j¯+4k¯ is

The angle between two vectors given by 6i¯+6j¯3k¯ and 7i¯+4j¯+4k¯ is

  1. A

    cos1(13)

  2. B

    cos1(53)

  3. C

    sin1(23)

  4. D

    sin1(53)

    Fill Out the Form for Expert Academic Guidance!l



    +91



    Live ClassesBooksTest SeriesSelf Learning



    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    If the angle between the vectors is ‘θ ’ then

    cosθ=A.B|A|.|B|

    cosθ=42+2412(36+36+9)(49+16+16)

    cosθ=54(9)(9)=23

    sinθ=53

    θ=sin1(53)

    Chat on WhatsApp Call Infinity Learn