The brakes applied to a train moving at 90 km/h produces a retardation of 5 m/s. What distance will it cover before coming to a stop?

The brakes applied to a train moving at

90 km / h

produces a retardation of

5 m / s

. It will cover a distance of

62.5 m

before coming to rest.
Initial speed

u = 90 km / h

= 90 \times \frac{5}{18} m / s

= 25 m / s

Final speed,

= 0

- 5 m / s^{2}

.
Let the distance covered before coming to rest be

s

.
Using, Newton's equation of motion,

v^{2} = u^{2} + 2 as

\Rightarrow 0 = 25 \times 25 - 2 \times 5 \times s

\Rightarrow 0 = 625 - 10 \times s

\Rightarrow 10 \times s = 625

m

\Rightarrow s = 62.5 m

The brakes applied to a train moving at $90 km / h$ produces a retardation of $5 m / s$ . What distance will it cover before coming to a stop?