The work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h is [[1]] J

The work required to be done to stop a car of

1500 kg

moving at a velocity of

60 km / h

208333.3 J

.
Given:
Mass of the car

(m)

= 1500 kg

The initial velocity of the car

(u) = 60 km / h

Converting velocity to m/s:

= \frac{60 \times 1000}{60 \times 60}

\Rightarrow = \frac{50}{3} m / s

Since the car stops the final velocity of it

v = 0 m / s

Using the formula

v^{2} = u^{2} + 2 as

where, acceleration is

a

and

s

is displacement

{(0)}^{2} = {(\frac{50}{3} m / s)}^{2} + 2 as

2 as = - \frac{2500}{9} {(\frac{m}{s})}^{2}

as = - \frac{2500}{18} {(\frac{m}{s})}^{2}

To calculate the work done

W = F \times s

Where,

F = force applied

F = mass \times acceleration

W = (m \times a) \times s

\Rightarrow W = m \times (a \times s)

\Rightarrow W = 1500 kg \times (- \frac{2500}{18}) {(\frac{m}{s})}^{2}

W = - 208333.3 J

Negative sign indicates that the direction of work is opposite to the direction of the displacement of the car.

The work required to be done to stop a car of $1500 kg$ moving at a velocity of $60 km / h$ is [[1]] $J$