MCQsMoving Charges and Magnetism Class 12 MCQ with Answers

Moving Charges and Magnetism Class 12 MCQ with Answers

The chapter “Moving Charges and Magnetism” is an important part of Class 12 Physics. It explains how moving electric charges create magnetic fields and how these magnetic fields affect other moving charges. This topic is not only interesting but also very useful, as it helps us understand many devices and technologies that we use in daily life.In this chapter, you will learn about the connection between electricity and magnetism, which together are known as electromagnetism. It introduces key concepts like the Biot-Savart Law, Ampere’s Circuital Law, and Lorentz Force. These ideas explain how magnetic fields are created by electric currents and how they interact with charged particles.

One of the exciting parts of this chapter is understanding how a charged particle behaves when it moves through a magnetic field. For example, it can travel in a circular path or even a spiral depending on the situation. This knowledge is used in devices like cyclotrons, which are particle accelerators, and in instruments that measure magnetic fields.

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    To help you prepare for exams, we have created a set of multiple-choice questions (MCQs) on this chapter. These questions cover all the important topics and test your understanding of the concepts. Each question comes with an answer and explanation, so you can learn from your mistakes and improve.

    Practicing these MCQs will help you get a better grip on the chapter. It will also prepare you for board exams and competitive exams like JEE and NEET. Whether it’s solving numerical problems or understanding theoretical concepts, these questions will make your preparation easier and more effective.

    So, start practicing and make sure you master the concepts of “Moving Charges and Magnetism.” It’s not just a chapter in your syllabus but also a gateway to understanding the wonders of electromagnetism!

    MCQs with Answers

    Question: Which of the following laws is used to determine the direction of magnetic force on a moving charge in a magnetic field?

    A) Ohm’s Law

    B) Fleming’s Left-Hand Rule

    C) Biot-Savart Law

    D) Ampere’s Law

    Answer: B) Fleming’s Left-Hand Rule

    Explanation: Fleming’s Left-Hand Rule is used to find the direction of the magnetic force experienced by a moving charge in a magnetic field.

    Question: A charged particle moves in a magnetic field perpendicular to its velocity. What type of path will it follow?

    A) Straight Line

    B) Parabolic Path

    C) Circular Path

    D) Elliptical Path

    Answer: C) Circular Path

    Explanation: When a charged particle moves perpendicular to the magnetic field, it experiences a centripetal force that causes it to move in a circular path.

    Question: The SI unit of the magnetic field is:

    A) Tesla

    B) Gauss

    C) Weber

    D) Ampere

    Answer: A) Tesla

    Explanation: The SI unit of the magnetic field is Tesla (T), which is equivalent to one Weber per square meter.

    Also Check: NCERT Solutions for Class 12 Physics Chapter 4: Moving Charges and Magnetism

    Question: What is the magnetic force on a stationary charge in a magnetic field?

    A) Maximum

    B) Minimum

    C) Zero

    D) Depends on the charge

    Answer: C) Zero

    Explanation: A stationary charge does not experience any magnetic force because the force depends on the motion of the charge (F = q(v x B)).

    Question: Which device is used to measure the strength and direction of a magnetic field?

    A) Galvanometer

    B) Voltmeter

    C) Ammeter

    D) Magnetometer

    Answer: D) Magnetometer

    Explanation: A magnetometer is specifically designed to measure the strength and direction of magnetic fields.

    Question: The force on a moving charge in a magnetic field is maximum when the angle between velocity and the magnetic field is:

    A) 0°

    B) 45°

    C) 90°

    D) 180°

    Answer: C) 90°

    Explanation: The magnetic force is given by F = qvB sinθ. It is maximum when θ = 90°.

    Question: What is the formula for the radius of the circular path of a charged particle moving in a perpendicular magnetic field?

    A) r = mv/qB

    B) r = qvB/m

    C) r = qB/mv

    D) r = m/qvB

    Answer: A) r = mv/qB

    Explanation: The radius of the circular path is determined by equating the centripetal force to the magnetic force: mv²/r = qvB.Question: Which of the following does not affect the magnitude of the magnetic force on a charged particle?A) Charge of the particle

    B) Velocity of the particle

    C) Magnetic field strength

    D) Mass of the particle

    Answer: D) Mass of the particle

    Explanation: Magnetic force depends on charge (q), velocity (v), and magnetic field (B), but not on the mass of the particle.

    Question: What is the direction of the magnetic field inside a solenoid carrying current?

    A) Circular around the axis

    B) Perpendicular to the axis

    C) Parallel to the axis

    D) Opposite to the current direction

    Answer: C) Parallel to the axis

    Explanation: The magnetic field inside a solenoid is uniform and parallel to its axis, as determined by the right-hand rule.

    Also Check: NCERT Exemplar Solutions for Class 12 Physics Chapter 4 – Moving Charges And Magnetism

    Question: Which of the following quantities remains constant for a charged particle moving in a magnetic field?

    A) Velocity

    B) Kinetic Energy

    C) Acceleration

    D) Magnetic Force

    Answer: B) Kinetic Energy

    Explanation: In a magnetic field, the force does no work, so the kinetic energy of the particle remains constant.

    Question : A current-carrying conductor placed in a uniform magnetic field experiences a force because of:

    A) The charge in the conductor

    B) The magnetic field produced by the conductor

    C) The interaction of the conductor’s current with the external magnetic field

    D) The electric field in the conductor

    Answer: C) The interaction of the conductor’s current with the external magnetic field

    Explanation: The force arises due to the interaction between the current in the conductor and the external magnetic field (Lorentz force).

    Question: The magnetic moment of a current loop depends on:

    A) The number of turns, current, and area of the loop

    B) Only the area of the loop

    C) Only the current in the loop

    D) The magnetic field strength

    Answer: A) The number of turns, current, and area of the loop

    Explanation: Magnetic moment (

    MM

    ) is given by

    M=nIAM = nIA

    , where

    nn

    is the number of turns,

    II

    is the current, and

    AA

    is the area.

    Question: The force between two parallel current-carrying conductors is:

    A) Always attractive

    B) Always repulsive

    C) Attractive if currents are in the same direction

    D) Repulsive if currents are in the same direction

    Answer: C) Attractive if currents are in the same direction

    Explanation: Parallel currents in the same direction attract each other due to the magnetic field interaction.

    Question: If the length of a current-carrying conductor in a magnetic field is doubled, the force acting on it:

    A) Remains the same

    B) Doubles

    C) Halves

    D) Becomes zero

    Answer: B) Doubles

    Explanation: The magnetic force is

    F=BILF = BIL

    , so if

    LL

    is doubled,

    FF

    also doubles.

    Question: What is the magnetic field at the center of a circular current-carrying loop of radius

    rr

    and current

    II

    ?

    A)

    mu0I/2r2\\mu_0 I / 2r^2

     

    B)

    mu0I/2r\\mu_0 I / 2r

     

    C)

    mu0I/r\\mu_0 I / r

     

    D)

    mu0Ir/2\\mu_0 I r / 2

     

    Answer: B)

    mu0I/2r\\mu_0 I / 2r

     

    Explanation: The magnetic field at the center of a current loop is given by

    B=mu0I/2rB = \\mu_0 I / 2r

    .

    Question: What happens to the radius of a charged particle’s circular path if the magnetic field strength is doubled?

    A) Doubles

    B) Halves

    C) Remains the same

    D) Becomes zero

    Answer: B) Halves

    Explanation: The radius of the circular path is inversely proportional to the magnetic field strength (

    r=mv/qBr = mv / qB

    ).

    Question: Which device operates on the principle of converting electrical energy into mechanical energy using a magnetic field?

    A) Transformer

    B) Galvanometer

    C) Electric Motor

    D) Ammeter

    Answer: C) Electric Motor

    Explanation: An electric motor converts electrical energy into mechanical energy using the interaction between current and magnetic fields.

    Question : A charged particle enters a region with both electric and magnetic fields, and moves undeflected. What is the condition for this?

    A) Electric field equals magnetic field

    B) Magnetic force equals electric force

    C) Electric field is perpendicular to the magnetic field

    D) Electric force is zero

    Answer: B) Magnetic force equals electric force

    Explanation: For a particle to move undeflected,

    qE=qvBqE = qvB

    , or

    E=vBE = vB

    , ensuring the forces balance each other.

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